Linux’s latest vulnerability: Hit backspace 28 times, and you would gain access

Linux is generally regarded as a stable and secure operating system when compared to Windows, which is comparatively more resource-intensive and less secure.

This is why Linux is used in supercomputers, servers, etc, because it is flexible while being more secure than Windows. One reason for Linux’s secure nature may perhaps be that Linux occupies a tiny section of the Desktop market, and so hackers don’t bother with trying to find vulnerabilities in Linux. However, Linux itself is built around security, while Windows is built around usability, and this may also be a reason for the difference.

However, recently, many dangerous Linux vulnerabilities have started popping up, and each of these vulnerabilities can compromise an entire system fairly easily. Now, a new vulnerability has emerged in Linux, which enables anyone to break into just about any Linux distribution (Specifically the ones using a GRUB 2 bootloader, which is right now the preferred bootloader for Linux distros) just by pressing the backspace key 28 times. This would trigger the Grub 2 Rescue Shell, from where you can issue commands to the system.

The key to this vulnerability is the memory error that occurs when you press the backspace key 28 times. Major Linux Distros have already patched this vulnerability, but smaller community-led distros may take more time in patching this.

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